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33x^2+10x-75=0
a = 33; b = 10; c = -75;
Δ = b2-4ac
Δ = 102-4·33·(-75)
Δ = 10000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{10000}=100$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-100}{2*33}=\frac{-110}{66} =-1+2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+100}{2*33}=\frac{90}{66} =1+4/11 $
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